Answer:
Gravity on the moon, g = 1.69 m/s²
Step-by-step explanation:
It is given that,
Length of pendulum, l = 1 m
Time period, T = 4.82 seconds
We have to find the gravity of the moon. The time period of the pendulum is given by :
![T=2\pi\sqrt{(l)/(g)}](https://img.qammunity.org/2020/formulas/physics/high-school/ubsrbi0ssm0sh60spp9hui90dkxa633u0o.png)
g = acceleration due to gravity on moon
![g=(4\pi^2l)/(T^2)](https://img.qammunity.org/2020/formulas/physics/high-school/u68ygcwzx36vutc2kmm2vqojx61pe2h24w.png)
![g=(4\pi^2* 1\ m)/((4.82\ s)^2)](https://img.qammunity.org/2020/formulas/physics/college/eweqb8u1hjprdk9h4io53u9pcxaqvlz82y.png)
g = 1.69 m/s²
Hence, the gravity on the moon is 1.69 m/s².