Question

A spring with spring constant 20 N/m has a mass of 5.0 kg attached. The spring is compressed and released. What is the period of oscillation?

Answer 1

The period of oscillation is 3.14 sec.

Step-by-step explanation:

Given that,

Spring constant = 20 N/m

Mass = 5.0 kg

We need to calculate the time period

Using formula of time period

`T =2\pi\sqrt{(m)/(k)}`

m= mass

k = spring constant

`T =2*3.14\sqrt{(5.0)/(20)}`

`T =3.14\ sec`

Hence, The period of oscillation is 3.14 sec.