Answer:
The probability of choosing a black card then a white card, without
replacement is 24/91
Explanation:
* Lets explain how to solve the problem
- There is a box contain some cards
- There are 8 white cards in the box
- There are 6 black cards in the box
- Two cards are choosing from the box a black card and then a white
card, without replacement
∵ The number of the white cards in the box is 8
∵ The number of the black cards in the box is 6
∴ The total number of the cards in the box = 8 + 6 = 14
- We will chose the first card which is a black card
- We have 6 choices from 14 choices
∵ The number of the black cards is 6
∵ The total number of the cards is 14
∴ P(black) = 6/14 = 3/7
- Now the number of the black cards is 5 and the total number of the
cards is 13 because there is no replacement
- We will chose the second card which is a white card
- We have 8 choices from 13 choices
∵ The number of the white cards is 8
∵ The total number of the cards is 13
∴ P(white) = 8/13
- Lets find the probability of choosing a black card then a white card
∵ P(black) = 3/7 and P(white) = 8/13
∴ P(black and white) = 3/7 × 8/13 = 24/91
* The probability of choosing a black card then a white card, without
replacement is 24/91