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Is abc~def? If so, identify the similarity postulate or theorem that applies.

Is abc~def? If so, identify the similarity postulate or theorem that applies.-example-1

2 Answers

2 votes

Answer:

D- can't be determined

Explanation:

a p e x work

User Sebastian Rittau
by
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5 votes

Answer:

Similarity cannot be determined ⇒ answer D

Explanation:

* Lets revise the cases of similarity

1) AAA similarity : two triangles are similar if all three angles in the first

triangle equal the corresponding angle in the second triangle

- Example : In ΔABC and ΔDEF, m∠A = m∠D, m∠B = m∠E and

m∠C= m∠F then ΔABC ≈ ΔDEF by AAA

2) AA similarity : If two angles of one triangle are equal to the

corresponding angles of the other triangle, then the two triangles

are similar.

- Example : In ΔPQR and ΔDEF, m∠P = m∠D, m∠R = m∠F then

ΔPQR ≈ ΔDEF by AA

3) SSS similarity : If the corresponding sides of two triangles are

proportional, then the two triangles are similar.

- Example : In ΔXYZ and ΔLMN, if
(XY)/(LM)=(YZ)/(MN)=(XZ)/(LN)

then the two triangles are similar by SSS

4) SAS similarity : In two triangles, if two sets of corresponding sides

are proportional and the included angles are equal then the two

triangles are similar.

- Example : In triangle ABC and DEF, if m∠A = m∠D and
(BA)/(ED)=(CA)/(FD)

then the two triangles are similar by SAS

* Now lets solve the problem

- In the triangles ABC and DEF

∵ m∠B = m∠E = 105°

∵ AB/DE = 16/4 = 4

∵ AC/DF = 36/9 = 4

∴ AB/DE = AC/DF = 4

∴ The two pairs of sides are proportion

∵ ∠B and ∠E are not the including angles between the sides AB , AC

and DE , DF

∵ We could not find the including angles from the information of the

problem

∴ We cannot prove the similarity

* Similarity cannot be determined

User Chirag Lukhi
by
8.7k points

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