What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?

Question

asked Nov 7, 2020 86.7k views

2 Answers

Sweenish · Answer 1 · 2020-11-08T15:58:14+0000

Answer:
$x\geq -2$

Explanation:

Given the inequality
$2(3x - 1) \geq 4x -6$ you need to solve for "x".

Apply Distributive property on the left side of the equation:

$6x - 2 \geq 4x -6$

Now add 2 to both sides:

$6x - 2+(2) \geq 4x -6+(2)$

$6x \geq 4x -4$

The next step is to subtrac
from both sides:

$6x-(4x) \geq 4x -4-(4x)$

$2x \geq -4$

And finally, divide both sides by 2:

$(2x)/(2)\geq  (-4)/(2)\\\\x\geq -2$

Fredericka Hartman · Answer 2 · 2020-11-13T18:19:27+0000

For this case we must find the value of the variable "x" of the following expression:

$2 (3x-1) \geq4x-6$

We apply distributive property to the terms within parentheses:
$6x-2 \geq4x-6$

We subtract 4x on both sides:

$6x-4x-2 \geq-6\\2x-2 \geq-6$

We add 2 to both sides:

$2x \geq-6 + 2\\2x \geq-4$

We divide between 2 on both sides:

$x \geq \frac {-4} {2}\\x \geq-2$

Answer:

$x \geq-2$