Question

What is the escape speed (in km/s) from an Earth-like planet with mass 6.5e+24 kg and radius 55.0 × 105 m? Use the gravitational constant G = 6.67 × 10-11 m3 kg-1 s-2.

Answer 1

Escape velocity, v = 12.6 km/s

Step-by-step explanation:

It is given that,

Mass of earth like planet,
`m=6.5* 10^(24)\ kg`

Radius of planet,
`r=55* 10^5\ m`

The escape velocity of a planet is given by the following formula as:

`v=\sqrt{(2Gm)/(r)}`

G = universal gravitational constant

`v=\sqrt{(2* 6.67* 10^(-11)\ m^3kg^(-1)s^(-2)* 6.5* 10^(24)\ kg)/(55* 10^5\ m)`

v = 12556.05 m/s

or

v = 12.6 km/s

Hence, this is the required solution.