Question

The maximum force measured on a 3.72 m wire is 0.731 N when the magnetic field is 0.093 T. What current flows through the wire? O 2.36 A O 225A O 2.11 A O 218

Answer 1

Current, I = 2.11 A

Step-by-step explanation:

It is given that,

Length of the wire, L = 3.72 m

Maximum force on the wire, F = 0.731 N

Magnetic field, B = 0.093 T

We have to find the current flowing the wire. The force acting on the wire is given by :

`F=lLB\ sin\theta`

When
`\theta=90`, F = maximum

So,
`F=ILB`

`I=(F)/(LB)`

`I=(0.731\ N)/(3.72\ m* 0.093\ T)`

I = 2.11 A

So, the current flowing through the wire is 2.11 A. Hence, the correct option is (c).