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How many electrons leave a 9.0V battery every minute if it is connected to a resistance of 1.4?? O 80x 1020 O 6.7x 1020 O 5.1 x 1021 O 24x 1021

1 Answer

5 votes

Answer:

2.4 x 10^21

Step-by-step explanation:

V = 9 V, R = 1.4 ohm, t = 1 minute = 60 second

Use Ohm's law

V = I R

I = V / R

I = 9 / 1.4

I = 6.43 A

Now use Q = I t

Q = 6.43 x 60 = 385.7 C

Number of electrons passing in 1 minute , n

= total charge in one minute / charge of one electron

n = 385.7 / (1.6 x 10^-19) = 2.4 x 10^21

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