Question

A 6.00 V battery has an internal resistance of 0.8322 What is the terminal voltage if it is connected in series to a circuit with a total resistance of 7380 O 5.89 V O 591V 5.87V O 5.99

Answer 1

The terminal voltage will be 5.99 volt.

(d) is correct option.

Step-by-step explanation:

Given that,

Voltage = 6.00

Internal r= 0.8322 ohm

Total resistance R =7380 ohm

We need to calculate the current

Using current formula

`I=(V)/(R+r)`

Put the value into the formula

`I = (6)/(7380+0.8322)`

`I=0.000812\ A`

We need to calculate the voltage drop due to internal resistance

`V' = Ir`

`V'=0.000812*0.8322`

`V'=0.00067\ volt`

Now, The terminal voltage will be

`V''=6-V'`

`V''=6-0.00067`

`V''=5.99\ volt`

Hence, The terminal voltage will be 5.99 volt,