Question

What current is produced if 1473 sodium ions flow across a cell membrane every 3.4ju8? 0 5.81 pA O 694 pA O 7.76 pA 5.99 pA

Answer 1

69.4 pA

Step-by-step explanation:

n = number of sodium ions = 1473

e = magnitude of charge on each sodium ion = 1.6 x 10⁻¹⁹ C

t = time taken to flow across the membrane = 3.4 x 10⁻⁶ sec

Total Charge on sodium ions is given as

q = n e eq-1

Current produced is given as

`i = (q)/(t)`

Using eq-1

`i = (ne)/(t)`

Inserting the values

`i = ((1473)(1.6* 10^(-19)))/(3.4* 10^(-6))`

i = 69.4 x 10⁻¹² A

i = 69.4 pA