Answer: From the given gases, the greatest rate of effusion is of
![CH_4](https://img.qammunity.org/2020/formulas/chemistry/middle-school/yx8mmo1fz0d0o6z1dg0b9ydlzy58tccj8d.png)
Step-by-step explanation:
Rate of effusion of a gas is determined by a law known as Graham's Law.
This law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:
![\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}](https://img.qammunity.org/2020/formulas/chemistry/middle-school/2ypmmy0g0pn6piiben9dzv60rlsubt7ic0.png)
It is visible that molar mass is inversely related to rate of effusion. So, the gas having lowest molar mass will have the highest rate of effusion.
For the given gases:
Molar mass of
![NH_3=17g/mol](https://img.qammunity.org/2020/formulas/chemistry/college/6x4hstbp9rg90vnrkp3qyouhqmduhzmhvq.png)
Molar mass of
![HCl=36.5g/mol](https://img.qammunity.org/2020/formulas/chemistry/college/hef1y7jsj84hjz6mp47una8e837i4qf8zj.png)
Molar mass of
![CH_4=16g/mol](https://img.qammunity.org/2020/formulas/chemistry/college/oxqdnoehf951mgcz5ekig1raatebzd9oku.png)
Molar mass of
![Ar=40g/mol](https://img.qammunity.org/2020/formulas/chemistry/college/oszv7i9b6v325060gmlmgsvmuz4gaa0zwc.png)
Molar mass of
![HBr=81g/mol](https://img.qammunity.org/2020/formulas/chemistry/college/ulyu7fvi2hgiri8gq2gwo50ctwhg5lkanv.png)
The molar mass of methane gas is the lowest. Thus, it will have the greatest rate of effusion.
Hence, the greatest rate of effusion is of
![CH_4](https://img.qammunity.org/2020/formulas/chemistry/middle-school/yx8mmo1fz0d0o6z1dg0b9ydlzy58tccj8d.png)