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The potential difference between two parallel plates is 227 V. If the plates are 6.8 mm apart, what is the electric field between them? O S.0x10 N/C O 28 x 10* N/C O 4.1 x 10 N/C O 3.3 x 10 N/C

1 Answer

2 votes

Answer:


E=3.3* 10^4N/C

Option D is the correct answer.

Step-by-step explanation:

Electric field, E is the ratio of potential difference and distance between them.

Potential difference, V = 227 V

Distance between plates = 6.8 mm = 0.0068 m

Substituting,


E=(V)/(d)=(227)/(0.0068)=3.3* 10^4N/C

Option D is the correct answer.

User Juris
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