Question

What net external force is exerted on a 1100-kg artillery shell fired from a battleship if the shell is accelerated at 2.40×104 m/s2? What is the magnitude of the force exerted on the ship by the artillery shell?

Answer 1

Answer: The force exerted on the artillery shell is
`2.64* 10^6N` and the magnitude of force exerted on the ship by artillery shell is
`2.64* 10^6N`

Step-by-step explanation:

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

`F=ma`

where,

F = force exerted on the artillery shell

m = mass of the artillery shell = 1100 kg

a = acceleration of the artillery shell =
`2.40* 10^4m/s^2`

Putting values in above equation, we get:

`F=1100kg* 2.40* 10^4m/s^2\\\\F=2.64* 10^6N`

Now, according to Newton's third law, every action has an equal and opposite reaction.

So, the force exerted on the artillery shell will be equal to the force exerted on the ship by artillery shell acting in opposite direction.

Hence, the force exerted on the artillery shell is
`2.64* 10^6N` and the magnitude of force exerted on the ship by artillery shell is
`2.64* 10^6N`

Answer 2

Force exerted, F = 2.64 × 10⁷ Newton

Step-by-step explanation:

It is given that,

Mass of the artillery shell, m = 1100 kg

It is accelerated at,
`a=2.4* 10^4\ m/s^2`

We need to find the magnitude of force exerted on the ship by the artillery shell. It can be determined using Newton's second law of motion :

F = ma

`F=1100\ kg* 2.4* 10^4\ m/s^2`

F = 26400000 Newton

or

F = 2.64 × 10⁷ Newton

So, the force exerted on the ship by the artillery shell is 2.64 × 10⁷ Newton.