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What are the values of a, b, and c in the quadratic equation 0 = x2 – 3x – 2?

a = , b = 3, c = 2
a = , b = –3, c = –2
a = , b = 3, c = –2
a = , b = –3, c = 2

User Wookiekim
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2 Answers

5 votes

Answer:

The values of a, b, and c in the quadratic equation are:


a=1\\b=-3\\c=-2

Explanation:

The general form of a quadratic equation is as follows


ax^2 + bx +c

Where a, b and c are real numbers that represent the coefficients of the quadratic equation and
a \\eq 0

In this case we have the following quadratic equation


x^2 - 3x - 2

Therefore, notice that:


a=1\\b=-3\\c=-2

User Hemanath
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7.7k points
5 votes

For this case we have that by definition, a quadratic equation is of the form:


ax ^ 2 + bx + c = 0

Where the roots are given by:


x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

We have the following equation:


x ^ 2-3x-2 = 0

Then, according to the definition, the values are:


a = 1\\b = -3\\c = -2

Answer:


a = 1\\b = -3\\c = -2

User Retendo
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8.7k points