Question

Glucose (C6H12O6) is an important biological molecule.

(Round the answer to nearest hundredth.)
What is the percent by mass of carbon in glucose?

Answer 1

40% (a)

Step-by-step explanation:

Option A- 40%, got it right on edge 2020

Answer 2

40.0%.

Step-by-step explanation:

• The molar mass of glucose (C₆H₁₂O₆) = 6(atomic mass of C) + 12(atomic mass of H) + 6(atomic mass of O) = 6(12.0 g/mol) + 12(1.0 g/mol) + 6(16.0 g/mol) = 180 g/mol.

• The atomic mass of C in glucose = 6(atomic mass of C) = 6(12.0 g/mol) = 72.0 g/mol.

∴ The percent by mass of carbon in glucose = [(The atomic mass of C in glucose)/(The molar mass of glucose)] x 100 = [(72.0 g/mol)/(180 g/mol)] x 100 = 40.0%.