Answer:
Here's what I get.
Explanation:
Part A. Equation in standard form
The question is asking you to find the equation of a straight line that passes through two points
Let x = the number of days
and y = the cost
Then the coordinates of the two points are (2,225) and (5,480).
(i) Calculate the slope of the line
![\begin{array}{rcl}m & = & (y_(2) - y_(1))/(x_(2) - x_(1))\\\\& = & (480 - 225)/(5 - 2)\\\\& = & (255)/(3)\\\\& = & 85\\\end{array}](https://img.qammunity.org/2020/formulas/mathematics/high-school/5rzj9cvpcwyfr6epguiuzp5o4voy37hva0.png)
In other words, the daily rental is $85/day.
(ii) Calculate the y-intercept
![\begin{array}{rcl}y & = & mx + b\\480 & = & 85 * 5 + b\\480 & = & 425 + b\\b & = & 55\\\end{array}](https://img.qammunity.org/2020/formulas/mathematics/high-school/zpqd4g1jrgvireafqts7a005zkmb204k7l.png)
(iii) Write the equation for the line
y = 85x + 55
That is, the cost is $55 plus $85/day
Part B. Equation in function notation
Replace y with ƒ(x)
ƒ(x) = 85x + 55
Part C. Graphing
Let's say you want to plot a graph of the rental cost for up to ten days.
(i) Calculate two points on the graph.
When x = 0, y = 85; when x = 10, y = 905.
(ii) Scale your axes
A good number of intervals is about ten.
Your x-axis should have tick marks at 1-day intervals.
Your largest y-value is 905. Ten intervals would make about $90/interval. However, you should round that up to $100/interval for easy interpolation.
Your y-axis will run from 0 to $1000 in $100 intervals.
Plot your two points and draw a straight line through them.
(iii) Axis labels
x represents the number of days, so the label on the x-axis could be "No. of days."
y represents the cost of renting the boat, so the label on the y-axis could be "Rental cost."
Your graph should resemble the one below.