Answer:
Option b: 6√3
Explanation:
Given expression is:
![√(36*3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/68in8hq13ssvzqi6xjv4fv17kvxjo7gxly.png)
We have to factorize the radicand in order to solve the given radical
So,
![= √(3*3*2*2*3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3y5mtyy7fxw5hd5i5sgled61v4rff5setj.png)
In order to solve the square root pairs are made:
![=√(2^2 * 3^2 * 3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/an5czrjm3hncl1ks8n9wkw33j4p7aozetc.png)
To evaluate the square root, the exponents are multiplied by 1/2
![= 2^{(2*(1)/(2))} *3^{(2*(1)/(2))} * 3^{((1)/(2))}\\=2*3*√(3) \\=6√(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/itdzagxfz6msowucx2ifokb1hlkmtsg1e1.png)
Hence, option b is correct ..