Question

PLEASE HELP AS FAST AS POSSIBLE PLEASE

Find the product of (-8y2 + 3) and (-4y - 3).

A) 32y3 + 24y2 - 12y - 9

B) -32y3 - 24y2 + 12y - 9

C) 12y3 - 12y - 9

D) -8y2 - 4y - 9

Answer 1

A) 32y³ + 24y² - 12y - 9

Explanation:

(-8y² + 3)(-4y - 3) = (-8y² x -4y) + (-8y² x -3) + (3 x -4y) + (3 x -3)

= 32y³ + 24y² - 12y - 9

Answer 2

The product of
`-8y^2+3` and
`-4y-3` is:

`32y^3+24y^2-12y-9`

Explanation:

We are asked to find the product of the two expressions which are given by:

`-8y^2+3` and
`-4y-3`

i.e.

we are asked to find the product of a quadratic and a linear polynomial.

We are asked to find the result of:

`(-8y^2+3)\cdot (-4y-3)`

Hence, on using the distributive property we have:

`-8y^2(-4y-3)+3(-4y-3)\\\\=-8y^2* -4y-8y^2* (-3)+3* (-4y)+3* (-3)\\\\i.e.\\\\=32y^3+24y^2-12y-9`

The correct answer is: Option: A