Question

A 140 g ball at the end of a string is revolving uniformly in a horizontal circle of radius 0.537 m. The ball makes 2.27 revolutions in a second. What is its centripetal acceleration?

Answer 1

109.13 rad/s^2

Step-by-step explanation:

m = 140 g = 1.4 kg, r = 0.537 m, f = 2.27 rps

The centripetal acceleration is given by

a = r ω^2

a = r x (2 π f)^2

a = 0.537 x ( 2 x 3.14 x 2.27)^2

a = 109.13 rad/s^2