Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = 1/4(x – 12). What is the standard form of the equation for this line?

Answer 1

-¼x + y = -2

Explanation:

First, convert to Slope-Intercept Form by moving "1" to the other side of the equivalence symbol to get y = ¼x - 2, then finally convert to Standard Form by moving "-¼x" to the other side of the equivalence symbol to end up with -¼x + y = -2. Do you understand?