A half-filled cylindrical water tank has a water level of 20 feet high. The tank can hold 6000 cubic feet of water. Find the diameter of the tank in feet to the nearest tenth

Question

asked Nov 18, 2020 143k views

1 Answer

Aprofromindia · Answer 1 · 2020-11-23T02:02:20+0000

Answer:

$D=13.8\ ft$

Explanation:

we know that

If the tank half-filled with water is at 20 feet, then the height of the tank is 40 feet

The volume of the cylindrical tank is equal to

$V=\pi r^(2)h$

we have

$h=40\ ft$

$V=6,000\ ft^(3)$

assume

$\pi =3.14$

substitute and solve for r

6,000=(3.14)r^(2)(40)

r^(2)=6,000/[(3.14)(40)]

$r=6.9\ ft$

Find the diameter

Remember that the diameter is two times the radius

$D=6.9*2=13.8\ ft$