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Almost doneeeeeeeeeeeeeeee

Almost doneeeeeeeeeeeeeeee-example-1

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We know that According to Algebra of Real Functions :

If f and g are two real functions which are defined under the same domain then (f + g)(x) = f(x) + g(x)

Given : f(x) = 2x - 1 and g(x) = x² - 3x - 2


:\implies (f + g)(x) = f(x) + g(x) = (2x - 1) + (x² - 3x - 2)


:\implies (f + g)(x) = f(x) + g(x) = x² - 3x + 2x - 1 - 2


:\implies (f + g)(x) = f(x) + g(x) = x² - x - 3

User Keith Vinson
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