We know that, Final Amount in Compound Interest is given by :
![\bigstar\;\;\boxed{\mathsf{Amount = Principal\left(1 + (Rate\;of\;interest)/(100)\right)^(Number\;of\;Years)}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/x2wfp4v0cw7eggd1zt1qzd80cqstglebv0.png)
Given :
● Principal = $5000
● Rate of interest = 1.25
● Number of Years = 10
Substituting the values in the Formula, We get :
![\implies \mathsf{Amount = 5000\left(1 + (1.25)/(100)\right)^(10)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/7wwxa78wm1r0b0fnlij0kno9xzwqzy5yo5.png)
![\implies \mathsf{Amount = 5000\left(1 + (0.25)/(20)\right)^(10)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/1clpazzmb1eakak0cx7n670u52z2ab5et5.png)
![\implies \mathsf{Amount = 5000\left(1 + (0.05)/(4)\right)^(10)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/k3o9lcmdnlgn8rzppq86dn8g22hese9o9j.png)
![\implies \mathsf{Amount = 5000\left((4.05)/(4)\right)^(10)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/n6q2w5q3ti81flygb2sf52fwh8dzn4rfhl.png)
![\implies \mathsf{Amount = 5000* (1.0125)^(10)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/pda659wit0v9yc561ym396ik1bp2h1kvor.png)
![\implies \mathsf{Amount = 5661.354}](https://img.qammunity.org/2020/formulas/mathematics/high-school/pjw4i8l4xvzz99grbv5rh9duev2mclucyf.png)
Answer : $5661.354 money will be in the account 10 years later