Question

The angle of elevation from a buoy in the water to the top of a lighthouse is 68degrees. If a buoy is 300 ft from the base of the lighthouse, from the height of the lighthouse.

Answer 1

The height of the lighthouse is
`742.5\ ft`

Explanation:

Let

h -----> the height of the lighthouse

we know that

The tangent of angle of 68 degrees is equal to divide the height of the lighthouse by the horizontal distance from the buoy to the base of lighthouse

so

`tan(68\°)=(h)/(300)`

Solve for h

`h=(300)tan(68\°)=742.5\ ft`