Answer:
The current in the heater is 12.5 A
Step-by-step explanation:
It is given that,
Power of electric heater, P₁ = 1400 W
Power of toaster, P₂ = 1150 W
Power of electric grill, P₃ = 1560 W
All three appliances are connected in parallel across a 112 V emf source. We need to find the current in the heater. We know that in parallel combination of resistors the current flowing in every branch of resistor divides while the voltage is same.
Electric power,
![P_1=V* I_1](https://img.qammunity.org/2020/formulas/physics/college/reyd4h2u1sdo3shnz1gvjr5f3sb32ksuu7.png)
![I_1=(P_1)/(V)](https://img.qammunity.org/2020/formulas/physics/college/mv61n03c3u52ymlwqy7swhicts0jdax7bk.png)
![I_1=(1400\ W)/(112\ V)](https://img.qammunity.org/2020/formulas/physics/college/cm58htlygvfx0dbq59i50870dqd1g0vqcr.png)
![I_1=12.5\ A](https://img.qammunity.org/2020/formulas/physics/college/50ie30kpa9y9csjtvlw4fr4k15gj8qbv0u.png)
So, the current in the heater is 12.5 A. Hence, this is the required solution.