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Find the missing factor B that makes the equality true

42x^5y^4=(-7x^3y)(B)​

1 Answer

3 votes

Answer:

-6x^2 y^3 = B

Explanation:

42x^5y^4=(-7x^3y)(B)​

Solve for B

Divide by -7

42x^5y^4/-7=(-7x^3y)(B)/-7

-6 x^5 y^4 = x^3 y B

Divide by x^3

-6 x^5 y^4/x^3 = x^3 y B​/x^3

-6 x^5/x^3 y^4 = By

-6 x^2 y^4

Divide by y

-6x^2 y^4/y = By/y

-6x^2 y^3 = B

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