Question

HELP!!THANKS FOR ACCURACY

Answer 1

`\bf tan^2(x)-1=0\implies tan^2(x)=1\implies tan(x)=\pm√(1) \\\\\\ tan^(-1)[tan(x)]=tan^(-1)(\pm 1)\implies x=tan^(-1)(\pm 1)\implies x= \begin{cases} (\pi )/(4)\\\\ (3\pi )/(4)\\\\ (5\pi )/(4)\\\\ (7\pi )/(4) \end{cases}`