Question

Formula One race cars are capable of remarkable accelerations when speeding up, slowing down, and turning corners. At one track, cars round a corner that is a segment of a circle of radius 95 m at a speed of 68 m/s. What is the approximate magnitude of the centripetal acceleration, in units of g?

Answer 1

Centripetal acceleration of the car is (4.96 g) m/s²

Step-by-step explanation:

It is given that,

Radius of circle, r = 95 m

Speed of the car, v = 68 m/s

We need to find the centripetal acceleration. It is given by :

`a_c=(v^2)/(r)`

So,
`a_c=((68\ m/s)^2)/(95\ m)`

`a_c=48.67\ m/s^2`

Since, g = 9.8 m/s²

So,

`a_c=(4.96\ g)\ m/s^2`

So, the magnitude of the centripetal acceleration is (4.96 g) m/s². Hence, this is the required solution.