Question

Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.1 kg attached to it and has a length of 5 m. Pendulum 2 has a ball of mass 0.9 kg attached to a string of length 1 m. How does mass of the ball affect the frequency of the pendulum?

Answer 1

Step-by-step explanation:

For pendulum 1 :

Mass, m₁ = 0.1 kg

Length, l₁ = 5 m

For pendulum 2 :

Mass, m₂ = 0.9 kg

Length, l₂ = 1 m

The time period the simple pendulum is given by :

`T=2\pi\sqrt{(L)/(g)}`..........(1)

And we know that frequency f is given as :

`f=(1)/(T)`

`f=\frac{1}{2\pi\sqrt{(L)/(g)}}`

From equation (1) it is clear that the time period and frequency depend on the length of the bob and acceleration due to gravity only. It is independent of its mass.