Question

A mass attached to a spring oscillates and completes 53 full cycles in 28 s. What is the time period (in s) and frequency (in Hz) of this system? period s frequency Hz

Answer 1

Step-by-step explanation:

It is given that, a mass attached to a spring oscillates and completes 53 full cycles in 28 s. Frequency of the system is given by the number of oscillations or vibrations per second. Here, the frequency of this system is given by :

`f=(no\ of\ oscillations)/(time)`

`f=(53)/(28)`

f = 1.89 Hertz

The relationship between the frequency and the time period of the spring is inverse i.e.

`T=(1)/(f)`

`T=(1)/(1.89\ Hz)`

T = 0.52 seconds

Hence, this is the required solution.