Answer:
The flux of the net electric field is
![2.26*10^(5)\ Nm^2/C](https://img.qammunity.org/2020/formulas/physics/college/dpkjrpo50o8v75enl2j0oy4xddm288ze3h.png)
Step-by-step explanation:
Given that,
Charge
![q= 2.00 \mu C](https://img.qammunity.org/2020/formulas/physics/college/1t4n4af9gkm80w4y0l4d7g4ht15p3n1ipl.png)
Electric field E = 100 N/C i
Radius R = 10.0 cm
We need to find the flux. It can be calculate using Gauss's law
The flux of the net electric field
![\phi=(q)/(\epsilon_(0))](https://img.qammunity.org/2020/formulas/physics/college/jcai7wjcytj7e4wqifatror82akh5p2idy.png)
![\phi=(2.00*10^(-6))/(8.85*10^(-12))](https://img.qammunity.org/2020/formulas/physics/college/wdfhng9erjr5pa1v9eeb6kgwxmi1kpyegm.png)
![\phi=2.26*10^(5)\ Nm^2/C](https://img.qammunity.org/2020/formulas/physics/college/rfj2xuurnq1an0ltpa0wboxaiewnjd86jk.png)
Hence, The flux of the net electric field is
![2.26*10^(5)\ Nm^2/C](https://img.qammunity.org/2020/formulas/physics/college/dpkjrpo50o8v75enl2j0oy4xddm288ze3h.png)