Question

What is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants? Assume that the contribution of protons from H2SO4 is near 100 %.Ba(OH)2(aq)+H2SO4(aq)→

Answer 1

Answer : The net ionic equation will be,

`Ba^(2+)(aq)+SO_4^(2-)(aq)\rightarrow BaSO_4(s)`

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : It is defined as the ions present on reactant and product side that do not participate in the reactions. That means the same ions present on both the sides.

The given balanced ionic equation will be,

`BaSO_4(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+H_2O(aq)`

The ionic equation in separated aqueous solution will be,

`Ba^(2+)(aq)+2OH^-(aq)+2H^+(aq)+SO_4^(2-)(aq)\rightarrow BaSO_4(s)+2H^+(aq)+2OH^-(aq)`

In this equation,
`H^+\text{ and }OH^-` ions are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

`Ba^(2+)(aq)+SO_4^(2-)(aq)\rightarrow BaSO_4(s)`