Question

Using the quadratic Formula to solve 2x^3=4x-7 what are the values of x

Answer 1

`x=1(+/-)0.5i√(10)`

Explanation:

we know that

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`2x^(2)=4x-7`

`2x^(2)-4x+7=0`

so

`a=2\\b=-4\\c=7`

substitute

`x=\frac{4(+/-)\sqrt{(-4)^(2)-4(2)(7)}} {2(2)}`

`x=\frac{4(+/-)√(-40)} {4}`

Remember that

`i=√(-1)`

`x=\frac{4(+/-)2i√(10)} {4}`

`x=1(+/-)0.5i√(10)`