Question

You are helping with some repairs at home. You drop a hammer and it hits the

floor at a speed of 8 feet per second. If the acceleration due to gravity (g) is
32 feet/second, how far above the ground (h) was the hammer when you
dropped it? Use the formula:
V = 2gh

Answer 1

`h=(1)/(8) feet`

Explanation:

In order to be able to solve this problem you just have to clear the formula for height:

V=2gh

`(V)/(2g)=H`

`(8)/(64)=H`

`(1)/(8)=H`

So the height from which the hammer is dropped is 1/8 feet.

Answer 2

1 foot.

Step-by-step explanation

That is not the correct formula. Correct is V^2 = 2gh where h = the height

so the equation is:

8^2 = 2*32* h

h = 64/ 64 = 1 foot.