So, for the equation itself cannot be a solution due to the ordered pair isn't a solution to the equation.
But I can solve what both x and y is, so, hopefully it'll help...
Solve the equation for x by finding a , b , and c of the quadratic then applying the quadratic formula.
x = − 5 ± √ − y + 27
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Subtract 10 x from both sides of the equation.
y = − x 2 + 2 − 10 x
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I hope this helps, as always. I wish you the best of luck and have a nice day, friend..