Question

The area of the indoor sports exhibition is shown below.

What is its perimeter?
m
What is its area?

Answer 1

Explanation:

The perimeter of the circular part of the sports exhibition can be found with the formula
`\pi`r.The equation is halved from the 2
`\pi`r as it is half a circle.

perimeter of circular part=17
`\pi`

Perimeter of the sports exhibition:

(4000/100)+10+10+68+33+17
`\pi`+34+(700/100)

=202+17
`\pi`

=255m(nearest whole number)

For the area, find the total area of the representive shapes

The two rectangles:10*40+68*33

=2644

The area of the semi circle (:
`\pi`r^2)/2

=17*17*
`\pi`/2

=144.5
`\pi`

Total area:

2644+144.5
`\pi`

=3098m^2(nearest whole number)

Answer 2

hello!

AREA
First find the area of the indoor sports park. Start by finding the area of the two rectangles using length times width (as shown in the first attachment).
Find the area of the half circle by finding the area of a circle () then dividing by 2.
Rect. 1 + Rect. 2 + Circle = Area
2244 + 400 + 908 (div'd by 2) = 3098 m^2
PERIMETER
The perimeter of the rectangles were found by adding up all the side lengths, and the perimeter (circumference) of the circle was found by using .
Rect. 1 + Rect. 2 + Circle = Perimeter
202 + 100 + 107 (div'd by 2) = 355.5 (or 356)