Question

Please anyone I’ll mark as a branlist

Answer 1

the first option is the answer, r = √6

Explanation:

`hypotenuse = \sqrt{opposite {}^(2) + adjacent {}^(2) }`

hypotenuse = q = √12

adjacent = p = √6

opposite = r

substitute the values into the hypotenuse formula

`q = \sqrt{r {}^(2) + p {}^(2) }`

`√(12) = \sqrt{r {}^(2) + ( √(6) ) {}^(2) }`

`( √(12) ) {}^(2) = r {}^(2) +6`

`12 = r {}^(2) + 6`

`12 - 6 = r {}^(2)`

`6 = r {}^(2)`

`√(6) = r`

`r = √(6)`