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Expand the logarithm log 7(3x − 2)^2

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\textbf{Transform}\\ \textrm{log} (7(3x -2)^2) \textbf{ into} \textrm{ log}(7) + \textrm{log}(3x-2)^2\\\\ \textbf{Expand} \\ \text{log}(3x-2)^2\\\\ \text{You can move 2 outside of }\text{log}(3x-2)^2\\\\ \textbf{Answer}\\ \text{log }7 + 2\text{ log}(3x-2)

User Sefier Tang
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