Question

An ideal transformer has 60 turns on its primary coil and 300 turns on its secondary coil. If 120 V at 2.0 A is applied to the primary, what voltage and current are present in the secondary?

Answer 1

Step-by-step explanation:

It is given that,

Number of turns in primary coil,
`N_p=60`

Number of turns in secondary coil,
`N_s=300`

Voltage in primary coil,
`V_p=120\ V`

Current in primary coil,
`I_p=2\ A`

We have to find the voltage and current in the secondary coli. Firstly calculating the voltage in secondary coil as :

`(N_p)/(N_s)=(V_p)/(V_s)`

`(60)/(300)=(120)/(V_s)`

`V_s=720\ Volts`

Now, calculating the current present in the secondary coil as :

`(N_p)/(N_s)=(I_s)/(I_p)`

`(60)/(300)=(I_s)/(2\ A)`

`I_s=0.4\ A`

Hence, this is the required solution.