Question

A 10 Ω resistor is connected to a 120-V ac power supply. What is the peak current through the resistor?

Answer 1

Peak current = 16.9 A

Step-by-step explanation:

Given that

RMS voltage = 120 Volts

`V_(rms) = 120 V`

AC is connected across resistance

`R = 10 ohm`

now by ohm's law

`V = i R`

`120 = i (10)`

`i_(rms) = (120)/(10) = 12 A`

now peak value of current will be given as

`i_(peak) = √(2) i_(rms)`

`i_(peak) = \sqrt2 (12) = 16.9 A`