Question

For f (x) = 3x +1 and g(x) = x^2-6, find (g/f)(x)

Answer 1

`(g/f) (x) =(x^2-6)/(3x+1)`

Explanation:

We have the following functions

`f (x) = 3x+1`

`g (x) = x^2-6`

To find
`(g/f)(x)` we must divide the function g(x) with the function f(x)

Then we perform the following operation

`(g/f) (x) =(x^2-6)/(3x+1)`

Finally we have that:

`(g/f) (x) =(x^2-6)/(3x+1)`

For
`x \\eq -(1)/(3)`