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An intercontinental ballistic missile goes from rest to a speed of 6.50 km/s in 60.0 s. In multiples of g, what is its acceleration?

User Saadiq
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1 Answer

3 votes

Answer:

The acceleration is
11.1g\ m/s^2

Step-by-step explanation:

Given that,

Speed
v= 6.50\ km/s=6.5*10^(-3)\ m/s

Time t = 60.0 sec

We need to calculate the acceleration

Using formula off acceleration


a = (\Delta v)/(t)


a=(v_(f)-v_(i))/(t)

We know that,

Missile goes from rest

So, Initial velocity =0

Put the value into the formula


a =(6.50*10^(3))/(60.0)


a=108.33\ m/s^2

On right hand side multiplying and dividing by g = 9.8m/s²


a=108.33*(g)/(g)

Put the value of g


a = (108.33)/(9.8)g\ m/s^2


a = 11.1g\ m/s^2

Hence, The acceleration is
11.1g\ m/s^2

User Alioguzhan
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