Answer:
The acceleration is
![11.1g\ m/s^2](https://img.qammunity.org/2020/formulas/physics/college/4ncrgq1qo3qiekl6ki2c1vdkvf3r1wvc16.png)
Step-by-step explanation:
Given that,
Speed
![v= 6.50\ km/s=6.5*10^(-3)\ m/s](https://img.qammunity.org/2020/formulas/physics/college/a8g8z0uge72fro5zsn7q1nb5yn2jr9lahk.png)
Time t = 60.0 sec
We need to calculate the acceleration
Using formula off acceleration
![a = (\Delta v)/(t)](https://img.qammunity.org/2020/formulas/physics/college/35joc3zvwieqrnvka4w8yyt2mtma0d7rrt.png)
![a=(v_(f)-v_(i))/(t)](https://img.qammunity.org/2020/formulas/physics/college/t5ww51wopfuzju4ck6aw11uep4yl7x658t.png)
We know that,
Missile goes from rest
So, Initial velocity =0
Put the value into the formula
![a =(6.50*10^(3))/(60.0)](https://img.qammunity.org/2020/formulas/physics/college/a0crqwhffckjqdqfv6sbk4zt9zoial0yfv.png)
![a=108.33\ m/s^2](https://img.qammunity.org/2020/formulas/physics/college/53ybbt424ymua1ffflju438hb8kerq8v3m.png)
On right hand side multiplying and dividing by g = 9.8m/s²
![a=108.33*(g)/(g)](https://img.qammunity.org/2020/formulas/physics/college/x8g0y6spl1cumt44ard2j19zneneprfxy1.png)
Put the value of g
![a = (108.33)/(9.8)g\ m/s^2](https://img.qammunity.org/2020/formulas/physics/college/tyrrrmpq0xbpyz84xfj913k158zfo6z05l.png)
![a = 11.1g\ m/s^2](https://img.qammunity.org/2020/formulas/physics/college/ttisejjae134g8hd3uoyncje075bvnqc25.png)
Hence, The acceleration is
![11.1g\ m/s^2](https://img.qammunity.org/2020/formulas/physics/college/4ncrgq1qo3qiekl6ki2c1vdkvf3r1wvc16.png)