Question

A 7.5-N net force is applied to a 47-kg object. What is the object's acceleration?

Answer 1

Object's acceleration, a = 0.15 m/s²

Step-by-step explanation:

It is given that,

Net force acting on the object, F = 7.5 N

Mass of an object, m = 47 kg

We need to find the acceleration of the object. It can be calculated using second law of motion as :

F = ma

a = acceleration of the object

`a=(F)/(m)`

`a=(7.5\ N)/(47\ kg)`

`a=0.15\ m/s^2`

So, the acceleration of the object is 0.15 m/s². Hence, this is the required solution.