Question

Find the amount of Heat conducted per second through a bar of aluminum if the cross sectional area is 30 cm the length of the bar is 1.5 m and one of the ends has a temperature of 25°C and the other has a temperature of 300°C. Thermal conductivity of Aluminum is 1.76 x 10^4 Cal cm / m^2 h°c Convert the units as needed

Answer 1

9680 cal

Step-by-step explanation:

A = cross-sectional area of the bar = 30 cm² = 30 x 10⁻⁴ m²

L = length of the bar = 1.5 m

T₁ = Temperature at one end of the bar = 25 °C

T₂ = Temperature at other end of the bar = 300 °C

k = Thermal conductivity of Aluminum = 1.76 x 10⁴ Cal cm /(m² ⁰C)

Q = amount of heat conducted per second

Amount of heat conducted per second is given as

`Q = (k A (T_(2) - T_(1)))/(L)`

Q = (1.76 x 10⁴) (30 x 10⁻⁴) (300 - 25)/1.5

Q = 9680 cal