Answer:
(a) 2.34 s
(b) 6.71 m
(c) 38.35 m
(d) 20 m/s
Step-by-step explanation:
u = 20 m/s, theta = 35 degree
(a) The formula for the time of flight is given by


T = 2.34 second
(b) The formula for the maximum height is given by


H = 6.71 m
(c) The formula for the range is given by


R = 38.35 m
(d) It hits with the same speed at the initial speed.