Question

A balloon was filled to a volume of 2.50 l when the temperature was 30.0∘c. What would the volume become if the temperature dropped to 11.0∘c.

Answer 1

2.34 L

Step-by-step explanation:

Assuming the pressure inside the balloon remains constant, then we can use Charle's law, which states that for a gas kept at constant pressure, the ratio between the volume of the gas and its temperature remainst constant:

`(V_1)/(T_1)=(V_2)/(T_2)`

where in this problem we have:

`V_1 = 2.50 L` is the initial volume

`V_2` is the final volume

`T_1 = 30.0^(\circ)C+273 = 303 K` is the initial temperature

`T_2 = 11.0^(\circ)C+273 = 284 K` is the final temperature

Substituting into the equation and solving for V2, we find the final volume:

`V_2 = (V_1 T_2)/(T_1)=((2.50 L)(284 K))/(303 K)=2.34 L`