Question

Which of the following are solutions to the following equation?

3x^2-48=0

A. 4
B. -4
C. 4sqr3
D. -4sqr3

Answer 1

A and B

Explanation:

We can add 48 to both sides of the equation to get

3x^2 = 48

Dividing by 3 on both sides,

x^2 = 16

Taking the square root of both sides,

x = +/- 4

So A and B are our answers.

Answer 2

Answer: Option A and Option B

`x=4` and
`x=-4`

Explanation:

We must find the solutions of the following equation

`3x^2-48=0`

Add 48 on both sides of the equality

`3x^2-48+48=48`

`3x^2=48`

Divide both sides of equality by 3

`(3)/(3)x^2=(48)/(3)`

`x^2=16`

Apply the square root on both sides of the equation

`x=\±√(16)`

`x=4` and
`x=-4`