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How many real and imaginary solutions does the equation X^2+x=11 contains?

User Rohit Raj
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1 Answer

5 votes

Answer:

Two

Explanation:

x² + x = 11

The degree of a polynomial will always tell us the maximum number of solutions

You have a second degree polynomial, so there are two possible solutions.

They are


x = (1)/(2) \left (-1 - 3√(5) \right )

and


x = (1)/(2) \left (-1 + 3√(5) \right )

The diagram below shows that the zeros are at (-3.854,0) and (2,854, 0), which are the decimal equivalents of the roots.

How many real and imaginary solutions does the equation X^2+x=11 contains?-example-1
User Nuno Silva
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