Question

The moment of inertia for a 5500 kg solid disc is 12100 kg-m^2. Find the radius of the disc? (a) 2.111 m (b) 2.579 m (c) 1.679 m (d) 2.574 m (e) 2.098 m (f) 2.457 m

Answer 1

The radius of the disc is 2.098 m.

(e) is correct option.

Step-by-step explanation:

Given that,

Moment of inertia I = 12100 kg-m²

Mass of disc m = 5500 kg

Moment of inertia :

The moment of inertia is equal to the product of the mass and square of the radius.

The moment of inertia of the disc is given by

`I=(mr^2)/(2)`

Where, m = mass of disc

r = radius of the disc

Put the value into the formula

`12100=(5500* r^2)/(2)`

`r=\sqrt{(12100*2)/(5500)}`

`r= 2.098\ m`

Hence, The radius of the disc is 2.098 m.