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5 votes
If x/9 < 2/5 and x is a positive integer, how many distinct values are possible for x?

1 Answer

5 votes

Answer:

3

Explanation:

Solving the inequality gives ...

x/9 < 2/5

x < 18/5 . . . . multiply by 9

Applying the problem restrictions, we have ...

0 < x < 3.6 . . . . . x is an integer

Solutions are {1, 2, 3}. There are 3 distinct possible values for x.

User Nelfi
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